Question

cards marked with 5,6,7,8......45 are placed in a box and mixed thoroughly. one card is drawn at random. find the probability that the number on the drawn card is: i] a perfect cube ii]a two digit prime number​

Answer 1

Let the Total outcome= 40 be n(t)

i) A perfect cube

from 5 to 45 , numbers which are perfect cube = {8 , 27} = 2.

Let the probability of getting a perfect cube be n(g).

Probability n(P)

$= \frac{n(g)}{n(t)}$

$= \frac{2}{40}$

$= \frac{1}{20}$

ii)

Favourable outcome ={11, 13, 17, 19, 23, 29, 31, 37, 41, 43, } = 10

Let n(x) be the probability of getting a two digit prime number.

Probability n(P)

$= \frac{n(x)}{n(t)}$

$= \frac{10}{40}$

$= \frac{1}{4}$

Answer 2

Answer:

2/41

10/41

Step-by-step explanation:

Total is 41 and not 40 because 45-5 is 40 but even the first card 5 is counted so 41.

Then find it out.

ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo