Question

cards marked with all 2 digit numbers are placed in a box and mixed thoroughly. one card is drawn at random find the probability that the number on the card is 1)divisible by 10
2)a perfect square 3)a prime number less than 25​

Answer 1

P(divisible by 10) = 9/90 = 1/10 =0.1

P(a perfect square) = 6/90

P(prime no less than 25) = 5/90

That's all !!

Please mark it as brainliest

Answer 2

The required probabilities are $\frac{1}{10} ,\frac{1}{15}$ and $\frac{1}{10}$.

Given:

Cards marked with all 2 digit numbers are placed in a box

To Find:

If one card is drawn at random, the probability that the number is

1) Divisible by 10

2) A perfect square

3) A prime number less than 25

Solution:

We can simply solve this problem by using the following mathematical process.

The two digit numbers are 10, 11, 12, 13, .......,99

Total number of two digit numbers = (99−9) = 90

1) To find the probability of the number being divisible by 10

Favourable outcomes are = (10,20,30,40,50,60,70,80,90)

Number of favourable outcomes = 9

P(Divisible by 10) = Number of favourable outcomes ÷ Total number of outcomes

Probability = $\frac{9}{90}$

Probability = $\frac{1}{10}$

2) To find the probability of the number being a perfect square

Favourable outcomes are = (16,25,36,49,64,81)

Number of favourable outcomes = 6

P(A perfect square number) = Number of favourable outcomes ÷ Total number of outcomes

Probability = $\frac{6}{90}$

Probability = $\frac{1}{15}$

3) To find the probability of the number being a prime number less than 25

Favourable outcomes are = (2,3,5,7,11,13,17,19,23)

Number of favourable outcomes = 9

P(A prime number less than 25) = Number of favourable outcomes ÷ Total number of outcomes

Probability = $\frac{9}{90}$

Probability = $\frac{1}{10}$

Hence, the required probabilities are $\frac{1}{10} ,\frac{1}{15}$ and $\frac{1}{10}$.

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