Question

cards marked with numbers 5,6,7..........30 are placed in a box and mixed throughly and 1 card is drawn at a random from the box what is the probablity of getting a prime number b)a multiple of 3 or 5 c) neither divisible by 5 nor 10

Answer 1

Total cards 26
1st



Multiple of three r 15 and 30
Probability =2/26
1/13


2nd

divisible by 5 10 r =5, 10,15,20,25,30
So total is 6
Not divisible by 5 and 10 r 20
Probability =20/26
10/13

Answer 2

Total no. of cards=26
P(E)= No. of favourable outcomes
-----------------------------------------
Total no. of outcomes

(a) P(a prime no.)= 8/26
=4/13

(b) P(a multiple of 3)= 9/26

(c) P(neither divisible by 10 nor 5)= 20/26
=10/13


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