Cards, numbered 3, 4, 5 ..., 25 are put in a box and mixed
thoroughly. A card is drawn at random from the box. Find the
probability that the card drawn bears (i) an even number (11) a
number divisible by 2 or 3.
Answers
Correct Question:
Cards, numbered 1, 2, 3, 4, 5 ..., 25 are put in a box and mixed thoroughly. A card is drawn at random from the box. Find the probability that the card drawn bears (i) an even number (ii) a number divisible by 2 or 3.
Step-by step explanation :
i) Total number of cards = 25
P(an even number) = 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24 = 12
Probability = Number of favourable outcomes/Total number of outcomes
12/25
ii) Total number of cards = 25
P(a number divisible by 2 or 3) = 2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24 = 16
Probability = Number of favourable outcomes/Total number of outcomes
16/25
But if the given question is correct then,
Question :
Cards, numbered 3, 4, 5 ..., 25 are put in a box and mixed thoroughly. A card is drawn at random from the box. Find the probability that the card drawn bears (i) an even number (ii) a number divisible by 2 or 3.
Step-by-step explanation :
i) Total number of cards = 23
P(an even number) = 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24 = 11
Probability = Number of favourable outcomes/Total number of outcomes
11/23
ii) Total number of cards = 23
P(a number divisible by 2 or 3) = 3, 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24 = 15
Probability = Number of favourable outcomes/Total number of outcomes
15/23
Question :--- Cards, numbered 3, 4, 5 ..., 25 are put in a box and mixed thoroughly. A card is drawn at random from the box. Find the probability that the card drawn bears (i) an even number (ii) a number divisible by 2 or 3. ?
Concept used :---
→ Probability :-- The number of ways of achieving success / the total number of possible outcomes.
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Solution :----
it is Given that , Numbers are from 3 to 25 continuously .
So,
→ Total Number of Possible Outcomes = 25 - 2(First number and second Number ) = 23 Total.
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Answer (1) :---
→ Total Even Numbers From 3 to 25 .
First Lets See what is a even Number ?
→ Even Number :-- Any integer that can be divided exactly by 2 is an even number.
So,
→ Even Numbers from 3 to 25 are = 4, 6, 8 , 10 , 12 , 14 , 16 , 18 , 20, 22 , and 24 = 11 Total .
So,
→ Required Probability of selecting a even Number out of total number will be = 11/23 ..
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Answer (2) :----
it has been said that a number either divisible by 2 or 3.
As told above all even Numbers are Multiple of 2 , So clearly we have Those 11 numbers...
And, Multiple of 3, upto 25 that are not Divisible by 2 are left as = 3, 9, 15 and 21 = 4 Total .
So, Total Number That will be divisible by 2 or 3 are = 11 + 4 = 15 Total .
Hence,