Math, asked by prathavish123, 3 months ago

Cards numbered from 1 to 18 are put in a box and mixed thoroughly. One card is

drawn at a random. Find the probability that the card drawn bears:

i. a prime number

ii. a factor of 18

iii. a number divisible by 2 and 3​

Answers

Answered by Answerer2908
8

Answer:

i. 6/18. = 1/3 ( six prime numbers 2,3,5,7,11,13,17 )

ii. 6/18 = 1/3 ( six factors of 18 1,2,3,6,9,18 )

iii. 3/18 = 1/6 ( three numbers divisible by both 2 and 3 they are. 6,12,18 )

Yeyy we did it...

Answered by TheMoonlìghtPhoenix
36

Answer:

Step-by-step explanation:

Let us assume that you have those 18 cards. These are numbered from 1 to 18.

Now, what are the prime factor between the numbers 1 to 18?

1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ,11, 12, 13, 14, 15, 16, 17 ,18

So, we have 7 prime factors. And the total cards are 18.

1. The answer is 7/18

Factor of 18 which means the number which when multiplied gives 18.

So, they are:-

1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ,11, 12, 13, 14, 15, 16, 17 ,18

2. The answer is 5/18

A number which is divisible by 2 or 3 is:-

1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ,11, 12, 13, 14, 15, 16, 17 ,18

So, the answer is :-

3. 3/18 = 1/6.

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