Carla is 5 years old and Jim is 13 years younger than Peter. One year ago,Peter's age was twice the sum of Carla's & Jim's age. Find the present age ofeach one of them.
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Carla : 5
Peter : x
Jim : x - 13
One year ago their ages were
Carla : 5 - 1 = 4
Peter : x - 1
Jim : x - 13 - 1 = x - 14
One year ago, Peter's age was twice the sum of Carla's and Jim's age which is written mathematically as
x - 1 = 2 (4 + x - 14)
Simplify and expand the right side of the above equation
x - 1 = 2 (x - 10)
x - 1 = 2x - 20
Add + 20 to both sides and simplify
x - 1 + 20 = 2x - 20 + 20
x + 19 = 2x
Subtract x to both sides and simplify
x + 19 - x = 2x - x
19 = x , Peter's age now
Jim's age: x - 13 = 19 - 13 = 6
Carla's age: 5
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