Carnalite is a double chloride of potassium and magnesium containing 36.86
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Let is consider 100g of Carnalite
Wt. of water = 38.86g
∴Wt. of KCl+MgCl
2
=(100−38.86)g=61.14g
Let Wt. of KCl=xgm
∴Wt. of MgCl
2
=(61.14−x)g
KCl+MgCl
2
→AgCl
By POAC
mole of Cl atom before reaction = mole of Cl atom reaction
mole of Cl In KCl + mole of Cl in MgCl
2
= mole of Cl in AgCl
mole of KCl+2× mole of MgCl
2
= mole of AgCl
100×74.5
0.458×x
+2×(61.14−x)100×95×0.458=
143.5
0.71
⇒
74.5
x
+
95
(61.14−x)2
=
143.5×0.458
700
=
65.72
700
calculating x=26.46 %
Explanation:
Hope it helps...
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