Question

Carnot engine takes one thousand kilo calories of heat from a reseervoir at 827^@C and exhausts it to a sink at 27^@C. How, much work does it perform? What is the efficiency of the engine?

Answer 1

Work done = 727.2 kcal. Efficiency of the engine = 72.72 %

Given:

Carnot engine takes one thousand kilo calories of heat from a reseervoir at 827°C.

Exhausts it to a sink at 27°C.

To find:

How much work does it perform?

What is the efficiency of the engine?

Explanation:

Efficiency of the engine = $\frac{T_{max}-T_{min}}{T_{max}}$

$T_{max}$ = 827°C = 827 + 273 = 1100 k

$T_{min}$ = 27°C  = 27 + 273 = 300 k

Efficiency of the engine = $\frac{1100-300}{1100}$ = 72.72 %

Efficiency of the engine = $\frac{work \ done }{energy \ supplied}$

Carnot engine takes one thousand kilo calories of heat

So Energy supplied = 1,000 kcal.

0.7272 = $\frac{work \ done }{1000}$

Work done = 727.2 kcal.

To learn more...

1)11. A Carnot engine has engine has efficiency of 80%. If its sink is at 127°C, then find the temperature of source.

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