Question

carnot engine working between 0 to 100 takes of 746 joules of heat from the source calculate work done by the engine heat ejected to sink

Answer 1

A Carnot engine has the same efficiency (i) between 100 K and 500 K and (ii) between T K and 900 K. Calculate the temperature T of the sink.
Maximum efficiency of an engine working between temperatures T2 and T1 is given by the fraction of the heat absorbed by an engine which can be converted into work is known as efficiency of the heat engine.

Mathematically,
In First case:
Efficiency, η = (T2 – T1) / T2
T2 = 500 K (temperature of the source)
T1 = 100 K (temperature of the sink)
Therefore,
η = (T2 – T1) / T2
= (500 – 100) / 500
= 4 / 5

In second case:
Efficiency, η = (T2 – T1) / T2
T2 = 900 K (temperature of the source)
T1 = T K (temperature of the sink)
Therefore,
η = (T2 – T1) / T2
= (900 – T) / 900

It is given that the Carnot engine has the same efficiency. Hence equating the efficiency of both the cases we will get:
(900 – T) / 900 = 4 / 5
5 (900 – T) = 3600
4500 – 3600 = 5T
900 / 5 = T
T = 180 K

Help u

Answer 2

ans is 180 i think.......