Carol has 4/5 of a tank of fuel.he uses 1/10 of a tank per day.how many days will his fuel last in a siplified fraction
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Answered by
1
Answer: 8 days
Step-by-step explanation:
Part of tank filled with fuel= 4/5
Per day usage= 1/10
No. of days until which fuel will last= 4/5 / 1/10
= 4/5 * 10
= 8
Answered by
1
Step-by-step explanation:
let number of days be x.
1/10*x=4/5
x=4×10/5=8 days.
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