Question

carpenter has two water pipes 60 and 72 diameter long respectively. He cuts them into equal length. What is the greatest possible length of each pipe

Answer 1

Answer:

The greatest possible length of each pipe is equal to the HCF of 60 dm & 62 dm . To find the HCF of these numbers use prime factorization method of calculating HCF. Hence, the greatest possible length of each pipe is 12 dm.

Answer 2

Answer:

The greatest possible length of each pipe is equal to the HCF of 60 dm & 73 dm . To find the HCF of these numbers use prime factorization method of calculating HCF. Hence, the greatest possible length of each pipe is dm. find and do it

Step-by-step explanation:

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