carries 9 kg nitre. What amount of gunpowder would contain 2.3
- Divide 7000 among A, B and C such that A gets 50% of what B gets and B gets 50% of what
C gets.
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Answer:
Let C=x
B= 2x
A= 21×B
A= 21 × 2x= 4x
A+B+C=700x+ 2x+ 4x
=70047x
=7004x
=100x
=400=C
B= 2x
=200
A= 4x
=100
The shares are 100Rs,200Rs,400Rs
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