Question

carries
A straight, current carrying conductor 2 m long carries a current of 15A.It placed in uniformed magnetic field of induction 5x10^-1wb/m2 with its length makes
angle of 90° find the force acting on conductor???​

Answer 1

Answer:

Given: i=10A,B=0.15 T,θ=45

∘

and l=2 m

Force on a current carrying wire of finite length =

F

=l(

i

×

B

)

Hence, magnitude of force, F=Bilsinθ

=0.15×10×2×sin45

∘

=

2

3

N

Answer 2

Explanation:

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