Cars tend to turn left with a probability of 0.4 (or 40% of the time) and go straight with a probability of 0.25.
What is the probability that a car turns right?
A-0.4
B-0.25
C-0.3
D-0.35
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D - 0.35 (35% of the time)
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Given info : Cars tend to turn left with a probability of 0.4 (or 40% of the time) and go straight with a probability of 0.25.
To find : the probability that a car turns right
solution : The probability, the car turns left, P(L) = 0.4
The probability, the car goes straight, P(S) = 0.25
The probability, the car turns right = P(R)
here L, R and S events are mutually exclusive and independents so, P(R) + P(L) + P(S) = 1
⇒P(R) + 0.40 + 0.25 = 1
⇒P(R) = 1 - 0.65 = 0.35
Therefore the probability, the car turns right is 0.35
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