Carson is training to run a race.He records the distance and the amount of times he runs each day.
Distance ( mi ) 2 | 3.5 | 3 | 4.5| Time ( min ) 18 | 31.5| 27 | 40.5 |
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Given:
Distance: 2 I 3.5 I 3 I 4.5 (in meters)
Time: 18 I 31.5 I 27 I 40.5 (in minutes)
To Find:
The speed at which he runs each day.
Solution:
According to the formula,
Speed = Distance / Time.
So,
When, Distance = 2m and Time = 18 min.
Speed = 2/18 = 0.11 m/min.
When, Distance = 3.5m and Time = 31.5 min.
Speed = 3.5/31.5 = 0.11 m/min.
When, Distance = 3m and Time = 27 min.
Speed = 3/27 = 0.11 m/min.
When, Distance = 4.5m and Time = 40.5 min.
Speed = 4.5/40.5 = 0.11 m/min.
Hence, Carson travels the given distance at given time with same speed which is 0.11m/min.
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