Case (i) : If a light body A of mass m and a
heavy body B of mass M, both have same
momentum p, then the kinetic energy of the light
body A will be more than that of the heavy
body B.
CAN SOMEONE EXPLAIN WITH EXAMPLE
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Answer:
Explanation:
MV=mv
K. E. of heavy body=Psqr/2M
K. E. of lighter body=Psqr/2m
From above relation we can say k. E of lighter body is greater
narshana3107:
can u give an EXAMPLE
Suppose 1kg block is moving with 10m/s and 2kg block moving with 5m/s
Momentum of both block
1kg×10m/s=2kg×5m/s k. E of 1kg block=1/2×1×(10m/s) ^2=50j k. E. Of 2kg block=1/2×2kg×(5m/s) ^2=25j
understood
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