Question

CASE STUDY - 1

In a survey of 50 persons of an apartment, it was found that 15 persons read Magazine A, 16 persons read Magazine B, 16 persons read Magazine C, 8 read both A and B, 10 read both B and C, 7 read both C and A, 5 read all the three Magazines​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

23 persons do not read magazine

Step-by-step explanation:

According to the question:

$n(A) = 15 , n(B) = 16 , n(C)= 16\\\\n(A\cap B) = 8, n(B\cap C) = 10, n(C\cap A) = 7, n(A\cap B\cap C) = 5\\\\ Now we know that \\\\n(A\cup B\cup C) = n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(C\cap A)+n(A\cap B\cap C)\\\\n(A\cup B\cup C) = 15+16+16-8-10-7+5=27\\\\\therefore 50-27=23 persons do not read magazine.$