. Case Study 3 :
The tunnels are defined as the underground passages that are used for the transportation purposes. These permit the
transmission of passengers and freights, or it may be for the transportation of utilities like water, sewage or gas etc.
The tunnel engineering is one of the most interesting disciplines in engineering. The work is complex and difficult
throughout its course, even though it is interesting.
Earth is excavated to make a road tunnel. The tunnel is a cylinder of radius 7 m and length 450 m. A level surface is laid
inside the tunnel to make road. The Diagram 1 shows the circular cross - section of the tunnel. The level surface is
represented by AB , the centre of the circle is O and ∠ = 90°. The space below AB is filled with rubble (debris
from the demolition buildings).
Steel girders are erected above the tracks to strengthen the tunnel. Some of these are shown in Diagram 2. The girders
are erected at 6 m intervals along the length of the tunnel, with one at each end. On the basis of the above
information, answer any four of the following questions:
a. What is the cross section area of tunnel before filling debris on ground plane ?
(a) 154 2 b. 140 2
c. 155 2 d. 145 2
b. What is the area of cross section of tunnel after filling debris on ground plane?
(a) 138 2 b. 140 2
c. 152 2 d. 145 2
c. What is the length of each girder ?
(a) 11 m b. 22 m c. 33 m d. 44 m
d. How many girders are erected ?
(a) 76 b. 75 c. 74 d. 73
Answers
Given : The tunnel is a cylinder of radius 7 m and length 450 m.
the centre of the circle is O and ∠OAB = 90°.
To Find :
cross section area of tunnel before filling debris on ground plane
cross section area of tunnel after filling debris on ground plane
How many girders are erected
Solution:
Cross section area of tunnel before filling debris on ground plane
= πR²
= (22/7)*7²
= 154 m²
area of cross section of tunnel after filling debris on ground plane
= 154 - (90/360) 154 + (1/2) * 7 * 7
= 154 - 38.5 + 24.5
= 154 - 14
= 140 m²
Tunnel length 450 m
girders erected at 6 m intervals along the length of the tunnel, with one at each end
= 450/6 + 1
= 75 + 1
= 76
Learn More:
The tunnel is a cylinder of radius 7 m and length 450 m.
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