Math, asked by lakshaysaini592, 11 hours ago

CASE STUDY: A City school is organizing Annual sports event in a rectangularshaped ground ABCD. The tracks are being marked with a gap of Im each in theform of straight lines. 120 flower pots are placed with a distance of 1 m eachalong AD. Shruti runs 1/3rd of the distance in the second line along AD and posther flag. Saanvi runs1/5th the distance AD in the eighth line and posts her flag.C-2BN3 4 5 6 789 10​

Answers

Answered by RisingStarVedika
0

Answer:

Given, A & D→100 flowers. (1m each).

Niharika →

4

1

th of AD in 2nd line.

∴x - coordinate =2

y - coordinate =

4

1

×100=25

∴ Niharika =(2,25)

Preet →

5

1

th AD in 8th line

∴x - coordinate =8

y - coordinate =

5

1

×100=20

∴ Preet =(8,20)

Hence, Distance between Niharika's & Preet's

Flag =

(8−2)

2

+(20−25)

2

=

36+25

=

61

cm

Rashmi has to place a blue flag exactly midway between Niharika's & Preet's.

∴x=

2

8+2

=

2

10

=5 & y=

2

25+20

=22.5

Hence, Rashmi (x,y)=(5,22.5)

So, Rashmi would post her flag in the 5th line at 22.5

Similar questions