CASE STUDY: An aeroplane leaves an Airport and flies due north at 300 km/h. At
the same time, another aeroplane leaves the same Airport and flies due west at
400 km/h.
i. Distance travelled by the first aeroplane in 1.5 hours
a. 450 km b. 300 km c. 150 km d. 600 km
ii. Distance travelled by the second aeroplane in 1.5 hours
a. 450 km b. 300 km c. 150 km d. 600 km
iii. Which aeroplane travelled a long distance and by how many km?
a. Second, 150 km b. Second, 250 km
c. First, 150 km d. Fist, 250 km
iv. How far apart the two aeroplanes would be after 1.5 hours?
a. 600 km b. 750 km c. 300 km d. 150 km
Answers
Answer:
Solution: Distance travelled by first aeroplane in1 1/2 hours = 300 × 3/2 km = 450 kmand that by second aeroplane =400 × 3/2 km = 600 kmPosition of the two aeroplane after 1 1/2 hours would be A and B as shown in Fig. 6.14. Thus the two aeroplanes will be 750 km apart after1 1/2 hours.
Answer:
Step-by-step explanation:
Definition of distance:
Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.
Given:
distance of first aeroplane = 300 km/h
distance of second aeroplane = 400 km/h
Find:
- Distance travelled by the first aeroplane in 1.5 hours
- Distance travelled by the second aeroplane in 1.5 hours
- Which aeroplane travelled a long distance and by how many km?
- How far apart the two aeroplanes would be after 1.5 hours?
Solution:
The distance covered by the first aircraft in 1 1/2 hours = 300 *3/2 km
= 450 km
The distance covered by the second aircraft = 400 *3/2 km
= 600 km.
Second aeroplane travelled a long distance = 150 km
After 1 and a half hours, the two aircraft would be in positions A and B
So, after 1 and a half hours, the two aircraft will be 750 kilometers apart.
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