Question

CASE STUDY
Ashish supplies bread and jams to a hospital and a school. Bread and jam are supplied in equi
number of pieces. Bread comes in a bunch of 8 pieces and Jam comes in a pack of 6 pieces. On
particular day, Ashish has supplied x packets of bread and y packets of jam to the school. On the sam
day, Ashish has supplied 3x packets of bread along with sufficient packets of jam to hospital. It
known that the number of students in the school are between 500 and 550.
i) How many students are there in school?
16
a) 508
b) 504
c) 512
d) 548
ii) How many packets of bread are supplied in the school?
a) 63 packets
b) 86 packets
c) 65 packets
d) 84 packets
iii) How many packets of jams are supplied in the school?
a) 63 packets
b) 86 packets
c) 65 packets
d) 84 packets
iv) How many packets of bread are supplied in the hospital?
a) 189 packets b) 252 packets c) 165 packets
d) 288 packets
5)How many packets of jams are supplied in the hosptital?
a) 248 packets
b) 252 packets c) 165 packets
d) 288 packets
​

Answer 1

1. c)512
2. a)63 packets
3. b)252 packets
4. 288 packets
5. 165 packets

hopes its help you

Answer 2

Answer:

a.504

b.63 packets

c.84packets

d.189 packets

e.252 packets

Step-by-step explanation:

a.Firstly we will find LCM (8, 6) =24. Now we will find a multiple of 24 in between 500 and

550 i.e., 504 or 528. Thus there 504 students in school.

b.For equal distribution of bread among each student, we need 504 pieces of bread. Hence, we

need (504/8=63) i.e. 63 packets of bread

c.For equal distribution of jam pieces among each student, we need 504 pieces of jam. Hence,

we need (504/6=84) i.e. 84 packets of jam.

d.For hospital, we need 3x packets of bread i.e. 3 # 63 = 189 packets of bread.

e.Since, number of bread pieces are 189 # 8 = 1512 , so we need same number

of jam pieces. Hence 252/ 6

1512 = packets of jam are distributed in the hospital.