Case Study Based – 1 A man sold a table and a chair together for ₹ 850 at a loss of 10 % on the table and a gain of 10 % on the chair. By selling them together for ₹ 950, he would have made a gain of 10 % on the table and loss of 10 % on the chair.
Now, answer the following questions on the basis of given information.
(i) If the cost price of one chair is ₹ x and that of one table is ₹ y, then what is the selling price (in ₹) of 1 one chair (given that loss of 10 % on the table and a gain of 10 % on the chair)?
A) 11x/10
B) 10x/11
C) x/10
D) x/11
(ii) If the cost price of one chair is ₹ x and that of one table is ₹ y, then what is the selling price (in ₹) of 1 one table (given that loss of 10 % on the table and a gain of 10 % on the chair)?
(A) y/10
(B) y/9
(C) 10y/9
(D) 9y/10
(iii) Given that loss on a chair is 10 % and gain 10 % on a table and the total selling price is ₹ 950. Linear 1 equation representing this situation is :
(A) 9x + 11y = 9500
(B) 11x + 9y = 9500
(C) 9x + 11y = 950
(D) 11x + 9y = 950
(iv) Cost price of one chair (in ₹) is : 1
(A) 900
(B) 700
(C) 200
(D) 300
(v) Cost price of one table (in ₹) is : 1
(A) 500
(B) 700
(C) 900
(D) 200
please i want correct answers only.
Answers
1 a,2b,3 c,4 d,5a, it can help u thnku
Given : A man sold a table and a chair together for ₹ 850 at a loss of 10 % on the table and a gain of 10 % on the chair. By selling them together for ₹ 950, he would have made a gain of 10 % on the table and loss of 10 % on the chair.
To Find : (i)Selling price (in ₹) of 1 one chair (a gain of 10 % on the chair)
Selling price (in ₹) of 1 one table (given that loss of 10 % on the table)
When total selling price is ₹ 950. Linear 1 equation representing this situation is
Cost price of one chair (in ₹)
Cost price of one table (in ₹)
Solution:
cost price of one chair is ₹ x
cost price of one table is ₹ y
sold a table and a chair together for ₹ 850 at a loss of 10 % on the table and a gain of 10 % on the chair.
=> y - (10/100)y + x + (10/100)x = 850
=> 0.9y + 1.1x = 850
=> 9y + 11x = 8500
By selling them together for ₹ 950, he would have made a gain of 10 % on the table and loss of 10 % on the chair
=> 11y + 9x = 9500
Adding both
=> 20y + 20x = 18000
=> x + y = 900
2y - 2x = 1000
=> y - x = 500
=> y = 700 and x = 200
Selling price (in ₹) of 1 one chair gain of 10 % on the chair = 11x/10
selling price (in ₹) of 1 one table t loss of 10 % on the table = 9y/10
Given that loss on a chair is 10 % and gain 10 % on a table and the total selling price is ₹ 950. Linear 1 equation representing this situation is
9x + 11y = 9500
Cost price of one chair = ₹ 200
Cost price of one table (in ₹) = ₹ 700
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