Question

Case Study Based-2 : A highway underpass a parabolic in shape.
Parabola : A parabola is the graph that results from p(x) = ax2 + bx + c.
Parabolas are symmetric about a vertical line known as the axis of symmetry,
(i) Graph of a quadratic polynomial is
(a) linear
(b) parabola
(c) circle
(d) sprial
(ii) If the highway overpass is represented by x2 + 2x – 15, then its zeroes are :
(a) (-3, 5)
(b) (-5, -3)
(c) (3, -5)
(d) (6, 0)
(iii) If the highway overpass is represented by x? – X-6, then its non-negative real zero is :
(a) 1
(b) 3
(c) 6.
(d) 5
(iv) The highway overpass is represented graphically. Zeroes of the polynomial can be expressed
graphically. Number of zeroes of polynomial is equal to number of points where the graph of the
polynomial.
(a) intersects y-axis
(b) intersects x-axis
(c) intersects both axes
(d) intersects z-axis
(o) The number of zeroes for the polynomial y = g(x) = (x +3) (x –1) – 3 X-
3
(a) 0
(b) 3
(c) 1
(d) 2
(x-5
is :
NW​

Answer 1

Answer:

I'll attach the answer

Step-by-step explanation:

Hope it helped you

Answer 2

Answer:

(i) Graph of a quadratic polynomial is

Sol : (b) parabola

A parabola is the graph that

results from p(x)=ax2 + bx+c

Parabolas are symmetric about a vertical line known as the Axis of Symmetry.

(ii) If the highway overpass is represented by x2 + 2x – 15, then its zeroes are :

x2 + 2x – 15=0

x2 +5x-3x -15=0

x(x+5) -3(x+5) =0

(x+5)=0 (x-3) =0

x=-5 x=3

X =(3, -5)

Sol:(c) (3, -5)

(iii) If the highway overpass is represented by x2 - x -6, then its non-negative real zero is

x2 - x -6 =0

x2-3x +2x-6=0

x(x-3) +2(x-3) =0

(x-3)=0 x+2=0

x=3 x=-2

Sol:(b) 3

(iv) The highway overpass is represented graphically. Zeroes of the polynomial can be expressed graphically. Number of zeroes of polynomial is equal to number of points where the graph of the polynomial.

Sol:(b) intersects x-axis

V) The number of zeroes for the polynomial y = g(x) = (x +3) (x –1) – 3( X-1/3)

Sol:(d) 2