Question

CASE STUDY BASED-4 Two dice, one blue and one red are thrown at the same time. The total number of possible outcomes are a) 6 b)12 c)36 d)216 The probability that the sum of two numbers appearing on the top of the dice is 2 a) 1/36 b)2/36 c)1/6 d)2/6 c) The probability that 5 will not come up either time is a)1/6 b)2/36 c)5/36 d)25/36 d) The probability that 5 will come up at least once is a)11/36 b)10/36 c)1/6 d)1/10 e)The probability that the sum of the two numbers appearing on the top of the dice is 13 a)1/36 b)0 c)2/36 d)6/36 ​

Answer 1

Answer:

Step-by-step explanation:

1. Total No of outcome=6*6=36 (c)

2. Sum of digits equal to 2 is possible

1+1 ( only one chance)

so P=1/36 (a)

3. outcome of 5 is possible

(5,1) (5,2) (5,3)(5,4) (5,5),(5,6)

(1,5)(2,5)(3,5)(4,5) (6,5)

total possibilities=11

Thus possibilities of not coming 5 =36-11=25

So P=25/36(d)

4.The possibilities of coming 5 at lest once=1-25/36=11/36(a)

5.The probability that the sum of the two numbers appearing on the top of the dice is :

max  sum of didigits on two dices=6+6=12

So 13 is not possible

hence P=0(b)