Question

`Case study based questions are compulsory. Attempt any four subparts of each question. Each subpart carries 1 mark. 17. Case Study Based-1 A coach is discussing the strategy of the game with his players. The position of players 28 is marked with 'x' in the figure. O JE H LE Scale: 1 Square = 1 unit பட்ட (1) IFO is taken as the origin the point whose abscissa is zero is (a) H (b) E (c) G (d) F (11) The distance between the player C and B is (a) 5 units (b) 4/2 units (c) 2/5 units (d) 5/2 units (iii) The player who is 6 units from x-axis and 2 units to the right of y-axis is at position. (a) J (b) B (c) I (d) A (iv) If (x y) are the coordinates of the mid-point of the line segment joining A and H then (a) x=-4 y = 2 (b) x = 2 y = 4 (c) x = -2 y = 4 (d) x = 4 y=-2 (v) According to sudden requirement coach of the team decided to increase one player in the 4th quadrant without increasing the total number of players so he decided to stru change the position of player F in such a way that F becomes symmetric to Dw.r.tx axis then new position of Fis (a) (3 4) (b) (3 -4) (c) (4 3) (d) (4 3) 5A `​

Answer 1

Answer:

The distance between the player C and B is (a) 5 units (b) 4/2 units (c) 2/5 units (d) 5/2 units (iii) The player who is 6 units from x-axis and 2 units to the right of y-axis is at position. (a) J (b) B (c) I (d) A (iv) If (x y) are the coordinates of the mid-point of the line segment joining A and H then (a) x=-4 y = 2 (b) x = 2 y = 4 (c) x = -2 y = 4 (d) x = 4 y=-2 (v) According to sudden requirement coach of the team decided to increase one player in the 4th quadrant without increasing the total number of players so he decided to stru change

Answer 2

Answer:

(1) If O is taken as the origin the point whose abscissa is zero is: (c) G

(2) The distance between the player C and B is: (b) 4√2 units.

(3) The player who is 6 units from x-axis and 2 units to the right of y-axis is at position: (a) J

(4)  If (x y) are the coordinates of the mid-point of the line segment joining A and H then (a) x=-4 y = 2

(5) then new position of F is: (b) (3 -4)

Step-by-step explanation:

(1) Abscissa is zero means, x = 0. So the point should lie on the Y-axis. In picture only 'G' is on Y-axis. So G's abscissa is 0.

(2) Suppose the vertical line from B and the horizontal line from C intersects at a point P. Then PBC will make a right angled triangle, whose base = CP = 4 units and height = PB = 4 units.

hypotenuse = BC = $\sqrt{CP^2 + PB^2}$ = $\sqrt{4^2+4^2}$ = $\sqrt{32}$ = $4\sqrt{2}$ units

(3) 6 units to the right of x axis, so y = +6 / -6. 2 units to the right of y-axis, so x = +2. Now at (2,6) there is no player, The right position will be (2,-6). and at that position J is there.

(4)  Position of A is (-4, 5)and position of H is (-4, -1),  

So position of midpoint = (x, y) = ($\frac{-4-4}{2} ,\frac{5-1}{2}$) = (-4, 2) . x = -4 and y = 2.

(5) The position of D is (3, 4). The symmetric point to D w.r.t x-axis means the distance from y - axis will remain same, but distance from x-axis will become negative.

Position of F = (3, -4).

For similar type of question visit the link given below:

https://brainly.in/question/1244786

https://brainly.in/question/42745158