(Case-Study (Co-ordinate Geometry): The Class IX students of a secondary school in Ludhiana have been allotted a rectangular plot of land for their gardening activity. Saplings of Gulmohar are planted on the boundary at a distance of 1m from each other. There is a lawn PQRS in the a) What are the co-ordinates of C taking A as origin?
(b) What are the co-ordinates of C taking A as origin?
(c)What is the shape and area of the lawn?
(d) Find the area of the lawn.
Answers
a) What are the co-ordinates of C taking A as origin?
Answer :-
→ the co-ordinates of C taking A as origin = (10,6) .
(b)What is the shape and area of the lawn ?
Answer :-
taking A as origin we have,
- P = (5,0)
- Q = (10,3)
- R = (5,6)
- S = (0,3)
so, using distance formula we get,
→ PQ = √[(10-5)² + (3-0)²] = √(25 + 9) = √34
→ QR = √[(5-10)² + (6-3)²] = √(25 + 9) = √34
→ RS = √[(0-5)² + (3-6)²] = √(25 + 9) = √34
→ PS = √[(0-5)² + (3-0)²] = √(25 + 9) = √34
since all sides are equal , therefore, we can conclude that,
PQRS is a square.
(d) Find the area of the lawn.
Answer :-
→ Area of square = (side)² = (√34)² = 34 unit².
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Answer:
i) (10, 6)
Step-by-step explanation:
the co-ordinates of C taking A as origin = (10,6)
.