CASE STUDY QUESTIONS:- II. Suppose the boy first runs a distance of 100 metres in 50 seconds in going from his home to the shop in the East direction, and then runs a distance of 100 metres again in 50 seconds in the reverse direction from the shop to reach back home from where he started (see the below Figure). 15. A boy is sitting on a merry-go-round which is moving with a constant speed of 10 m/s. This means that the boy is: *
Answers
Answer:
spinning the boy is spinning
Explanation:
Given : the boy first runs a distance of 100 metres in 50 seconds in going from his home to the shop in the East direction, and then runs a distance of 100 metres again in 50 seconds in the reverse direction from the shop to reach back home from where he started
To Find:
What will be the displacement of the boy?
(i) 200 m (ii) 0 m (iii) 150 m (iv) -200 m
Find the average speed of the boy.
(i) 1 m/s (ii) 2 m/s (iii) 3 m/s (iv) none of these
c. Find the velocity of the boy.
(i) 10m/s (ii) 4m/s (iii) 0 m/s (iv) 2 m/s
Solution:
Displacement = Final Position - Initial Position
as boy returns back to original position
Hence Final Position - Initial Position = 0
=> Displacement = 0 m
velocity = Displacement / Time
=> Velocity = 0/(50 + 50) = 0 m/s
Average Speed = Total Distance / Total Time
=>Average Speed = (100 + 100)/(50 + 50)
=> Average Speed = 2 m/s
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