CASE STUDY: Reema being a plant lover decides to open a nursery and she bought a few plants with pots. She wants to place pots in such a way that the number of pots in the first row is 3, in the second row is 5 and in the third row is 7 and so on.

a) If Reema wants to place 120 pots in total then the number of rows formed in this arrangement is?
b) Find the difference in number of pots placed in 8th row and 3rd row.
Answers
Given : Reema wants to place pots in such a way that number of pots in first row is 3, in second row is 5 and in third row is 7 and so on.
Reema wants to place 120 pots in total
To Find : total number of rows formed in this arrangement
How many pots are placed in last row?
difference in number of pots placed in 8th row and 3rd row
Solution:
AP
3 , 5 , 7 , ..........
a = 3
d = 2
rows = n
=> (n/2) (2*3 + (n-1)2) = 120
=> n(n+ 2) = 120
=> n = 10
10 Rows
Last row is 10th
= 3 + (10 - 1)2
= 3 + 18
= 21
difference in number of pots placed in 8th row and 3rd row
8th row = 3 + 7(2)
3rd row = 3 + 2(2)
Difference = 5(2)
= 10
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Answer:
@impersonatorr
•°•No. of rows = 10
and,
No. of pots in last row = 21
Hope, the solution is clear to you:))
