Question

cat 12° cat 38°cat 52° cat 60° cat 78°​

Answer 1

Answer:

$cot12cot38cot52cot60cot78=\frac{1}{\sqrt{3}}$

Step-by-step explanation:

Given cot12°cot38°cot52°cot78°cot60°

/*Rearranging the terms , we get

=cot12°cot78°cot38°cot52°cot60°

= cot(90-78)cot78°cot(90-52)cot52°cot60°

=(tan78°cot78°)(tan52°cot52°)cot60°

= 1×1×cot60°

$=cot60\degree$

$=\frac{1}{\sqrt{3}}$

Therefore,

$cot12cot38cot52cot60cot78=\frac{1}{\sqrt{3}}$

•••♪

Answer 2

Answer:

Step-by-step explanation:

Given cot12°cot38°cot52°cot78°cot60°

/*Rearranging the terms , we get

=cot12°cot78°cot38°cot52°cot60°

= cot(90-78)cot78°cot(90-52)cot52°cot60°

=(tan78°cot78°)(tan52°cot52°)cot60°

= 1×1×cot60°

Step-by-step explanation: