Question

Cat + table - turtle = 170cm, turtle + table-cat =130cm. Table = 150cm, cat = ? cm, turtle = ? cm? ???

Answer 1

Solution:

let Cat + table - turtle = 170cm ------eq1

turtle + table-cat =130cm ------eq2

put
Cat = 170cm-table+turtle

in eq2

turtle + table-170cm+table-turtle=130cm.

2table = 130+170 cm

table = 150 cm

Cat - turtle = 20 cm ------eq3

-Cat +turtle = -20cm ------eq4

if we compare the coefficient of eq3 &eq4,

we get that

$\frac{1}{ - 1} = \frac{ - 1}{1} = \frac{20}{ - 20} \\ \\ \frac{ - 1}{1} = \frac{ - 1}{ 1} = \frac{ - 1}{1}$

Since
$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}$


Thus the equation has no solution.

Answer 2

The question is incomplete without the figures.

However,

Considering the figures,

Inferences from the first picture:

Height of the table + cat - tortoise = 170

Inferences from the second picture:

Height of the table - cat + tortoise = 130  

Let us consider the height of the table, cat and tortoise to be x, y and z respectively.

Hence we get,

x+y-z=170  

x-y+z=130

Equating both the equations:

By addition,

x+y-z=170  

x-y+z=130

We get,

Height of two tables = 170 + 130

Height of two tables  = 300 cm

Therefore,

Height of one Table = 300 ÷ 2  = 150 cm

Hence, the height of the table is 150 cm.

The distance between the cat and the tortoise cannot be determined with the data available.

Read more on Brainly.in - https://brainly.in/question/6073027