Category 3, 7, 11, 15. . . . . . . Find the sum up to the 40th term of
(a) 3442 (b) 3443
(c) 3242 (d)3240
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Answer:
an=a+(n-1)d
an=3+(40-1)4
an=3+156
an=159
Sn=n/2(a+l)
S40= 40/2(3+159)
=20(162)
= 3240
Ans: 3240
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