Math, asked by darathijopaulin, 2 months ago

cauchys s integral theorem to find the value of z³/Z-(1/3)i dz

Answers

Answered by shubhamjangra259
0

Answer:

Integrate by parts using the formula ∫udv=uv−∫vdu ∫ u d v = u v - ∫ v d u , where u=z and dv=e−z d v = e - z .

hope it helps

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