Question

CB is a tangent from C to the circle and BA is a diameter. angle AOC =120degree. Find angle BCO. (a)30° (b)40° (c)35° (d)25°​

Answer 1

Answer:

a) 30°

Step-by-step explanation:

Because, as tangent is given this means there is an angle of 90° also.

And angle AOC = 120°

So, angle COB = 180° - 120°

= 60° (because, linear pair)

So , there will be a triangle BCO right angled at B.

So, by using Angle sum property of triangle.

60° + 90° + angle BOC = 180°

150° + angle BOC = 180°

angle BOC = 180° - 150°

therefore, angle BOC = 30°

Hope it helped you.....