Math, asked by himanshupandey18, 7 months ago

(CBSE 201
polynomial.
32. If a, ß are the zeros of the polynomial 2y2 + 7y+5, write the value of a+b+aß.
(CBSE 20​

Answers

Answered by rukumanikumaran
28

hope this helps u

Compare given equation with ay^2+by+c=0

a=2, b=7, c=5

Given zeroes are alpha and beta

i) alpha +beta = -b/a= -(7/2)

ii) alpha* beta = c/a =5/2

Value of

Alpha +beta +(alpha)(beta)

=-7/2 +5/2

=-2/2

=-1

Answered by mdp1175
8

Answer:

(-1)

Step-by-step explanation:

p(x)= 2y²+7y+5,

the polynomial is in the general form of ax²+bx+c

where a = 2, b=7, c=5

a (alpha), ß are zeroes.

a+ß = -b/a

a+ß = -(7)/2

a+ß = -7/2

aß = c/a

aß = 5/2

a+ß+aß = -7/2 + 5/2

a+ß+aß = -2/2

a+ß+aß = -1

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