(CBSE 201
polynomial.
32. If a, ß are the zeros of the polynomial 2y2 + 7y+5, write the value of a+b+aß.
(CBSE 20
Answers
Answered by
28
hope this helps u
Compare given equation with ay^2+by+c=0
a=2, b=7, c=5
Given zeroes are alpha and beta
i) alpha +beta = -b/a= -(7/2)
ii) alpha* beta = c/a =5/2
Value of
Alpha +beta +(alpha)(beta)
=-7/2 +5/2
=-2/2
=-1
Answered by
8
Answer:
(-1)
Step-by-step explanation:
p(x)= 2y²+7y+5,
the polynomial is in the general form of ax²+bx+c
where a = 2, b=7, c=5
a (alpha), ß are zeroes.
a+ß = -b/a
a+ß = -(7)/2
a+ß = -7/2
aß = c/a
aß = 5/2
a+ß+aß = -7/2 + 5/2
a+ß+aß = -2/2
a+ß+aß = -1
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