Question

(CBSE 2010)
A man goes 15 m due west and then 8 m due north.
How far is he from the starting point?​

Answer 1

please marks bresent marks

Answer 2

First the person moves from A to B and then B to C.

First the person moves from A to B and then B to C.His distance from the starting point is AC.

First the person moves from A to B and then B to C.His distance from the starting point is AC.AC can be calculated using Pythagoras Theorem.

First the person moves from A to B and then B to C.His distance from the starting point is AC.AC can be calculated using Pythagoras Theorem.Applying Pythagoras theorem

${ab}^{2} + {bc}^{2} = {ca}^{2}$

${(15)}^{2} + {(8)}^{2} = {x}^{2}$

$225 + 64 = {x}^{2}$

${x}^{2} = 289$

${x}^{2} = \sqrt{289 } = 17m$

hence the man is 17m from the starting point