Question

[CBSE 2012]
14. In the figure, AB || CD. If Z ABR = 45° and
ROD = 105° then find Z ODC.
AC
B
45°
105
R
D
ICRSE 2012

Answer 1

Answer:

Let us construct the lines OQand RP.∠ABO= ∠BPD = 45°In △OPD, ∠OPD +∠POD+∠ODP= 180°or, 45° +105° +∠ODP = 180°or, ∠ODP= 180° − 45° − 105° = 30°Thus, ∠ODC= 30°

Step-by-step explanation: