Question

CBSE 2012
26.) The sum of remainders obtained when
x° +(k+8)x + k is divided by X-2 and
when it is divided by x +1, is 0. Find the
value of k.​

Answer 1

Answer:

K = -26/3.

Step-by-step explanation:

g(x) = x - 2 = 0

= x = 2.

g(x) = x + 1 = 0

= x = -1.

Now, substitute x value to the equation.

=> x + ( k + 8 ).x + k = x + ( k + 8 ).x + k

=> 2 + ( k + 8 ).2 + k = -1 + ( k + 8 ).-1 + k

=> 1 + 2k + 16 + k = -1 + ( -k - 8 ) + k

=> 1 + 2k + 16 + k = -1 -k -8 + k

=> 17 + 3k = -9 +0k

=> 3k = -9 -17

=> 3k = -26

=> k = -26/3

¤ therefore, the value of k = -26/3.

¤ hence proved..

plz mark me as the brainliest answer..