Question

cbse class 10 maths chapter 3 ex. 3.3 question 1 whole
plese give answer I will let you brainliest​

Answer 1

Answer:

come in whatsp i will explain u 6005362691

Answer 2

Answer:

Using equation (1), we can say that s = 3 + t

Putting this in equation (2), we get

⇒

⇒ 5t + 6 = 36

⇒ 5t = 30⇒ t = 6

Putting value of t in equation (1), we get

s – 6 = 3⇒ s = 3 + 6 = 9

Therefore, t = 6 and s = 9

(iii) 3x – y = 3 … (1)

9x − 3y = 9 … (2)

5 = 14

⇒ x = 14 – 5 = 9

Therefore, x = 9 and y = 5

(ii) s – t = 3 … (1)

…(2)

please make me brainliest please