Question

CBSE class 11 A car accelerates from rest at constant rate of 2 m/s^2 for some time. Then, it retards at constant rate of 4m/s^2 and comes to rest. If the total time for which it remains in motion is 3seconds, what is the total distance travelled? No spamming or plagiarism. with step by step explanation please

Answer 1

Answer:

Explanation:

Let v,t  

1

​  

,t  

2

​  

 be the maximum velocity attained, time for which car accelerated and the time for which car retarded respectively

⇒t  

1

​  

=(v−u)/a=(v−0)/2=v/2

⇒t  

2

​  

=(v−u)/a=(0−v)/(−4)=v/4

Now it is given that,  

⇒t  

1

​  

+t  

2

​  

=3

⇒v/2+v/4=3

⇒v=4m/s