CBSE class 11
What is the equation for the total time taken when an object is thrown from a height and it reaches the ground? It's related to motion under gravity. please answer only if you know for sure
No spamming or plagiarism please i need help
Answers
Answer:
Multiply the height by 2, and divide the result by the object's acceleration due to gravity. If the object fell from 5 m, the equation would look like this: (2*5 m)/(9.8 m/s^2) =1.02 s^2. Take the square root of the result to calculate the time it takes for the object to drop.
maybe this will help you
mark me as your BRAINLIEST
Thankyou
t = √(2h/g) is the total time taken when an object is thrown from a height and it reaches the ground
Explanation:
Assumption its thrown horizontally
hence initial Vertical Velocity = 0
Height = h ( is the Vertical distance to be covered)
a = g = acceleration Due to gravity
Using S = ut + (1/2)at²
S = h
t = ? ( need to find)
u = 0
a = g
=> h = 0 + (1/2)gt²
=> t² = 2h/g
=> t = √(2h/g)
Learn More:
An object is thrown vertically upwards and rises to a height of 45 m ...
https://brainly.in/question/17918881
The height, y, of an object thrown into the air is known to be given by ...
https://brainly.in/question/12040785
A stone is thrown upwards from the ground with a velocity 'u'a) What ...
https://brainly.in/question/11273112