CBSE class 9 ch.1 number system
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Step-by-step explanation:
= 1/(1+√2) + 1/(√2+√3) + 1/(√3+√4) + ... + 1/(√8+√9)
= summation n=1 to 8 [ 1/(√n+√(n+1)) ]
= sum n=(1-8) [ (√n - √(n+1) )/(n-n-1) ]
= sum n =(1-8) ( √(n+1) - √n)
= √2 - 1 + √3 - √2 + √4 -√3 + √5 -√4 +.. +√9 - √8
= -1 + √9
= -1 + 3
= 2
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