Question

CBSE : Class X
Based on articles and their costs
4 tables and 3 chairs together cost *2250 and
3 tables and 4 chairs cost * 1950. Find the cost of
2 chairs and 1 table.​

Answer 1

let cost of table be X and cost of chair be Y.

4X +3Y =2250. .........(1)

3X + 4Y = 1950. ...........(2)

multiply (1) by 4 and (2) by 3

we get;

16X + 12Y = 9000. -

6X + 12Y = 5850

---------------

10X + 0. = 3150

10 X = 3150

X = 3150/ 10

= 315

Substitute X in (2) or (1),

3X + 4Y = 5850

3×315 + 4Y = 5850

945 + 4Y = 5850

4Y = 5850-945

= 4905

Y = 4905/4

= 1226.25

Now X = 315 and Y = 1226.25

For 1 table and 2 chair, the cost is,

=1X + 2Y

=1×315 + 2×1226.25

=315 + 2452.5

= 2767.5

Therefore ₹2767.5 is the final answer.

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