Question

CBSE
Maths (Standard)
Solve it

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Answer 1

Answer:

8:5

Step-by-step explanation:

Let distance b/w B1 and B2 be 1 unit

so b/w B2 and B3 the distance will be again 1 unit

then,

B1,B2,B3,B4,B5 = BB5 =(m= 5)

Similarly,distance b/w A1 and A2 be 1 unit and between A2 and A3 again 1 unit

then,A1,A2,A3,A4,A5,A6,A7,A8 = AA8=(n=8)

In ΔBB5C and ΔAA8C,

∠BCB5 = ∠ACA8(vertically oppo. Angle)

∠B5BC = ∠A8AC (Alternate angles)

so,ΔBB5C ~ ΔAA8C (AA Similarity)

AC/BC =AA8/BB5 (CPCT)

AC/BC = 8/5

AC:BC = 8:5

hope it helps....

Answer 2

hope the answer helps u :-