Math, asked by puttappanavarshashan, 1 month ago

CCT QUESTION 1)
Inspired by the “Swachh Bharat mission”, Piya and her friends Sunita, Kiya and Hiya decided to clean their society park. Her friends clean 2/5, 1/3 and 1/4 part of the park respectively.

Question i):How much part of the park will be left for Piya to clean?

Question.ii):Who will clean the maximum and minimum section of park?

Question .iii):If Sunita left after cleaning half of of the section of park assigned to her due to some reason ,then is it justified to say that Sunita and Hiya cleaned equal portions of park. Explain


pls explain with variable x and also find the total area of the park ​

Answers

Answered by maheswari2188
30

Answer:

Step-by-step explanation:

Attachments:
Answered by VaibhavSR
25

Answer:

1) Park left for Priya to clean=\frac{1}{60}

2) Maximum clean by Sunita=\frac{24}{60} and minimum by Piya=\frac{1}{60}

Step-by-step explanation:

Concept

  • Equal parts of a whole or a collection are represented by fractions. When we divide something into equal pieces, each part becomes a fraction of the whole.

Explanation

Given-Clean by friends 2/5 , 1/3 and 1/4

Find-Park left for clean Piya, who clean max and minimum section of park

Solution

Left area of Park=Total-Area cleaned by friend whole

                          =1-(\frac{2}{5} +\frac{1}{3} +\frac{1}{4} )\\1-(\frac{24+20+15}{60} )\\1-\frac{59}{60} \\\frac{60-59}{60} \\\frac{1}{60}

Maximum park clean by Sunita=\frac{24}{60}

Minimum part clean by Hiya=\frac{1}{60}

#SPJ3

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