Question

CCT question A soft drink is available in a cylindrical pack of radius 3.5cm and height 10cm .The cost of the soft drink is related to the quantity of drink in it at the rate of Rs 60 per litre .Now answer the following question(a)Find the capacity of this container (b) what is the cost of this soft drink( in round Rs)?(c) what is the curved surface area ? (d) what is the total surface area of this container ? (e) which concept is used in solving such questions?​

Answer 1

Explanation:

Given:-

A soft drink is available in a cylindrical pack of radius 3.5cm and height 10cm .The cost of the soft drink is related to the quantity of drink in it at the rate of Rs 60 per litre.

To find:-

(a)Find the capacity of this container

(b) what is the cost of this soft drink( in round Rs)?

(c) what is the curved surface area ?

(d) what is the total surface area of this container ?

(e) which concept is used in solving such questions?

Solution:-

Radius of the cylindrical pack of the soft drink (r) = 3.5 cm

Height of the cylindrical pack of the soft drink (h) = 10 cm

a)Capacity of the pack of the soft drink =

Volume of a cylinder

= πr^2h cubic units

=>(22/7)×(3.5)^2×10 cubic cm

=>(22×3.5×3.5×10)/7

=>(22×35×35×10)/(100×7)

=>269500/700

=>2695/7

=>385 cubic cm

Volume of the pack of the soft drink = 385 cm^3

we know that

1 litre = 1000 cubic cm

1 cubic cm = 1/1000 litres

=>385 cubic cm = 385/1000 = 0.385 litres

b)The cost of the soft drink per 1 litre = Rs.60

The cost of the soft drink of 0.385 litres

=>0.385×60

=>Rs.23.1

=>Rs 23(rounded it)

The cost of the drink = Rs.23

c)Curved surface area of a cylinder = 2πrh sq.units

=>2×(22/7)×3.5×10 sq.cm

=>2×22×0.5×10 sq.cm

=>2×22×5 sq.cm

=>220 sq.cm

Curved Surface Area of the pack = 220 sq.cm

d)Total surface area of a Cylinder=

2πr(r+h) sq.units

=>2×(22/7)×3.5×(3.5+10) sq.cm

=>(2×22×0.5×13.5) sq.cm

=>22×13.5 sq.cm

=>297 sq.cm

e) The given container is in the form of cylinder ,so Using the concept and formulae of cylinder.

Answer:-.

a)Capacity of the pack of the soft drink

=385 cm^3

b)The cost of the drink = Rs.23

c)Curved Surface Area of the pack = 220 sq.cm

d)Total surface area of the given pack = 297 sq.cm

e)The given container is in the form of cylinder ,so Using the concept and formulae of cylinder.

Used formulae:-

• Volume of a cylinder= πr^2h cubic units
• Curved surface area of a cylinder = 2πrh
• Total surface area of a Cylinder=
• 2πr(r+h) sq.units
• 1 litre = 1000 cubic cm

Answer 2

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Solution:-

Radius of the cylindrical pack of the soft drink (r) = 3.5cm

Height of the cylindrical pack of the soft drink (h) = 10cm

(a) Capacity of the pack of the soft drink => Volume of a cylinder

= πr^2h cubic units

= \frac{22}{7}

7

22

×(3.5)^2×10 cubic cm

= (22×3.5×3.5×10)/7

= (22×35×35×10)/(100×7)

= 269500/700

$= \frac{2695}{7}$

= 385 cubic cm

Volume of the pack of the soft drink = 385cm^3

As we know that,

1 litre = 1000 cubic cm

$1 cubic cm = \frac{1}{1000}$

$=> 385 cubic cm = \frac{385}{1000}$

= 0.385 litres

(b) The cost of the soft drink per 1 litre = Rs. 60

The cost of the soft drink of 0.385 litres

=> 0.385×60

=> Rs. 23.1

=> Rs. 23(rounded it)

The cost of the drink = Rs. 23

(c) Curved surface of area of a cylinder = 2πrh sq. units

=> 2×(22/7)×3.5×10 sq. cm

=> 2×22×0.5×10 sq. cm

=> 2×22×5 sq. cm

=> 220 sq. cm

Curved surface area of the pack = 220

(d) Total surface area of Cylinder = 2πr(r+h) sq. units

=> 2×22/7×3.5×(3.5+10) sq. cm

=> (2×22×0.5×13.5) sq. cm

=> 22×13.5 sq. cm

=> 297 sq. cm

(e) The given container is in the form of cylinder So, using concept and formula of cylinder.