CCT Weekly Practice (Mathematics)
Participating for social causes
An NGO decides to involve students of class X to initiate a drive to make people aware of
road etiquettes.As a part of the drive, a banner is created.
The shape of the banner that says “do not honk” is as shown in the figure.
Question 1:
The formula to calculate the perimeter of the banner is
(a) 2 (l + b)
(b) 2πrh + 2πr2
(c) πr + (2l + b)
(d) 2 (l + b) + πr2
Question 2:
The total surface area of the banner is
(a) 55860 cm2
(b) 70952 cm2
(c) 55880 cm2
(d) 70558 cm2
Question 3:
If the total cost of the cardboard used per banner is Rs. 83.79. Then the rate per m2 is:
(a) Rs 25
(b) Rs 15
(c) Rs 35
(d) Rs 45Question 4:
Let us assume that the chalan for not wearing a seat belt is Rs 1000 first time and it increases by
Rs. 50 each time after that in a month. If a driver is caught 10 times in a month for not wearing
a seat belt. Calculate the total fine paid by him.
(a) Rs 22500
(b) Rs 12500
(c) Rs 35000
(d) Rs 12250
Question 5:
Three slogans were finalized and the number of banners made for each slogan is in A.P. If the
total number of banners made is 90 and their product is 5130, then find the no. of banners for
each type of slogan.
(a) 7, 50, 33
(b) 3, 30, 57
(c) 5, 53, 32
(d) 7, 50, 30
Answers
Step-by-step explanation:
the banner is
(a) 2 (l + b)
(b) 2πrh + 2πr2
(c) πr + (2l + b)
(d) 2 (l + b) + πr2
Question 1: The formula to calculate the perimeter of the banner is :-
(a) 2 (l + b)
(b) 2πrh + 2πr2
(c) πr + (2l + b)
(d) 2 (l + b) + πr2
Answer :-
→ perimeter of semi - circle + perimeter of 3 sides of rectangle
→ (2πr/2) + (2l + b)
→ πr + (2l + b) (c) (Ans.)
Question 2) :- The total surface area of the banner is
(a) 55860 cm2
(b) 70952 cm2
(c) 55880 cm2
(d) 70558 cm2
Answer :-
→ TSA = Rectangle area + (1/2)πr²
→ TSA = (208 * 96) + (1/2) * (22/7) * (98)²
→ TSA = 40768 + 22 * 49 * 14
→ TSA = 40768 + 15092
→ TSA = 55860 cm² (a) (Ans.)
Question 3: If the total cost of the cardboard used per banner is Rs. 83.79. Then the rate per m² is:
(a) Rs 25
(b) Rs 15
(c) Rs 35
(d) Rs 45
Answer :-
→ Rate = Total cost / Total area
→ Rate = (83.79)/(55860/100000)
→ Rate = 83.79/5.586 = 15m² (B) (Ans.)
Question 4: Let us assume that the chalan for not wearing a seat belt is Rs 1000 first time and it increases by Rs. 50 each time after that in a month. If a driver is caught 10 times in a month for not wearing a seat belt. Calculate the total fine paid by him.
(a) Rs 22500
(b) Rs 12500
(c) Rs 35000
(d) Rs 12250
Answer :-
→ Chalan for 1st time is = Rs.1000 = a
→ Increased by = Rs.50 = d .
→ Driver caught = 10 time = n
so,
→ Total fine = (10/2)[2*1000 + (10-1)50] = 5(2000 + 450) = (2450 * 5) = Rs.12250 (B) (Ans.)
Question 5) :- Three slogans were finalized and the number of banners made for each slogan is in A.P. If the
total number of banners made is 90 and their product is 5130, then find the no. of banners for each type of slogan.
(a) 7, 50, 33
(b) 3, 30, 57
(c) 5, 53, 32
(d) 7, 50, 30
Answer :-
Let three banners are (a - d), a and (a + d) .
so,
→ (a - d) + a + (a + d) = 90
→ 3a = 90
→ a = 30 .
then,
→ (30 - d) * 30 * (30 + d) = 5130
→ (30² - d²) = 5130/30
→ 900 - d² = 171
→ d² = 900 - 171
→ d² = 729
→ d = ±27
taking d = 27,
- a - d = 30 - 27 = 3
- a = 30
- a + d = 30 + 27 = 57 .
therefore, option (b) is correct .
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