cd is a chord of circle(O,r) if cd=10 and m angle cod = 90 find the diameter of the circle
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Let the radius be x
sin angle ocd = x/10
sin 45 = x/10
√2/2 = x/10
x = 10√2/2
Diameter = 2 × x
= 2 × 10√2/2
= 10√2
sin angle ocd = x/10
sin 45 = x/10
√2/2 = x/10
x = 10√2/2
Diameter = 2 × x
= 2 × 10√2/2
= 10√2
gayatribhatt:
thnks...
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