CD is a diameter which meets chord AB in such that AE = BE = 4 cm. if CE = 3 cm find the radius of the circle
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Step-by-step explanation:
OE = r - 3
join OB [ radius of circle ]
in ∆ OBE, OB² = 4² + OE²
=> r² = 16 + (r - 3)²
=> r² = 16 + [ r² + 9 - 6r ]
=> r² = 16 + r² + 9 - 6r
=> r² = 25 + r² - 6r
=> 6r = 25
=> r = 25/6 => 4.16 cm
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