Question

CD is parallel to AB calculate y

Answer 1

In trianle ABC

2x+3x+4x=180°
9x=180°
x=180/9
x= 20°----(1)

since AB||CD
^ABC+^BCD= 180° (SUM OF ANGLES ON THE SAME SIDE OF TRAVERSAL IS 180)

3X+4X+^ACD =180°
3(20)+4(20)+^ACD=180° [x=20°]
60+80+^ACD =180°
140+^ACD=180°
^ACD=180°-140°
^ACD=40°


4X+^ACD+^Y=180(LINEAR PAIR)
80+40+Y=180
120+Y=180
Y=180-140
Y=40°


I HOPE THIS WILL HELP YOU