Question

ce -tan (A+B)
show that sinit-sin B
a sinA COSA- SinB COSB​

Answer 1

Answer:

The range of ‘Sin’ and ‘Cos’ function is [-1,1].

so the max value sin can have is 1.

Now, coming back to the ques we have

SinA+SinB=2

if we consider either SinA or SinB less than 1 , then other Sin has to be greater than 1 , in order to give the submission equal to 2.

For eg .

lets suppose Sin A = 0.5=(1/2)

0.5 + SinB = 2

Sin B = (2–0.5) = 1.5

Sin B > 1, which violates the fundamental range of Sin function i.e [-1,1].

Therefore both has to be equal to 1.

SinA=SinB=1

which implies A=B=90 degrees.

Cos (90) = 0

therefore, CosA+CosB = Cos(90) + Cos(90) =0.

Step-by-step explanation:

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Answer 2

Answer:

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